# QA – Placement Quizzes | Numbers, LCM and HCF | Question 1

What could be the maximum value of Y in the following equation given that neither of X, Y, Z is zero?

5X8 + 3Y4 + 2Z1 = 1103**(A)** 0**(B)** 7**(C)** 8**(D)** 9**Answer:** **(B)****Explanation:**

1 1 <- CARRY 5 X 8 + 3 Y 4 + 2 Z 1 -------- 11 0 3 --------

Clearly, X + Y + Z + 1 = 10

=> X + Y + Z = 9

Now, since neither of X, Y, Z can be zero, the value of Y will be maximum when X = Z = 1.

=> Max Y = 7

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